Published by:
CGP EDU Academic Team
Published on: August 14, 2026
5 litre solution of 0.4 M CuSO 4(aq) is electrolyzed using Pt electrode. A current of 482.5 ampere is passed for 4 minutes. The concentration of CuSO 4 left in solution is (Assume volume of solution to be remained unchanged):
Text Solution
Verified by ExpertsThe correct answer is:
B
Cu 2+ + 2e – → Cu
2mol 
mol
= 1.2 mol electrons
2 mole electrons then Cu +2 reacted = 1 mole
When 1.2 mole electrons then Cu +2 reacted = 
× 1.2 = 0.6
so, remaining Cu +2 moles = 2 – 0.6 = 1.4 moles
Remaining [CuSO 4 ] = 
= 0.28 M.
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